Here is a picture of a schematic showing the power source taken from the windings of the motor of a turntable.
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What I don’t understand is how is it that the output is higher than the input voltages. See where the input is 17.5 V yet after rectification it becomes 20 V. Where is the added voltage coming from especially when there is a voltage drop across the diode?
The 17.5vac is an RMS value of an AC voltage. The peak voltage for 17.5VAC is 17.5 times 1.414 or 24.47 volts. (1.414 is the square root of 2). The filter capacitor charges up to the peak value with out a load. Apparently the normal load will discharge the capacitor between sine wave peaks to 20VDC
@frogman Ah..so it is a result of converting AC to DC and the added voltage of peak rather than rms.
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